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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int i, j, p=0, a;
  5.  
  6. 	for(i=1; i<=10000; i++){
  7. 		for(j=1; j<i; j++){
  8. 			a=i%j;
  9. 			if(a==0){
  10. 				p=p+j;
  11. 			}
  12.  
  13. 		}
  14. 		if(i==p){
  15. 			printf("%d\n", p);
  16. 		}
  17. 		p=0;
  18. 	}
  19. 	return 0;
  20. }
  21.  
Success #stdin #stdout 0.17s 5292KB
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stdin
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10000
stdout
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6
28
496
8128
https://ideone.com/2VfEjV
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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