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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.   double go = 1.0;
  5.   double yon = 1.0;
  6.   double ans = 1e19;
  7.   int n = 0;
  8.  
  9.   while (go + yon < ans) {
  10.     go *= 5.0;
  11.     yon *= 4.0;
  12.     n++;
  13.   }
  14.  
  15.   printf("5^n+4^nが10^19を超える最小のnは%dです\n", n);
  16.   return 0;
  17. }
  18.  
Success #stdin #stdout 0s 5320KB
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5^n+4^nが10^19を超える最小のnは28です
https://ideone.com/326Xkt
language:
C (gcc 8.3)
created:
7 days ago
visibility:
public

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