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  1. class Solution:
  2.     def validPalindrome(self, s: str) -> bool:
  3.         i = 0
  4.         j = len(s) - 1
  5.         while i <= j:
  6.             if s[i].lower() != s[j].lower():
  7.                 skipL,skipR = s[i+1:j+1] , s[i:j]
  8.                 return (skipL == skipL[::-1]) or (skipR == skipR[::-1])
  9.             i+=1
  10.             j-=1
  11.  
  12.         return True
  13.  
Success #stdin #stdout 0.11s 14180KB
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https://ideone.com/H5ShBU
language:
Python 3 (python  3.12)
created:
2 days ago
visibility:
public

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