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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. #define endl '\n'
  4. #define int long long
  5. const int MOD = 158400;
  6. const int MOD2 = 998244353;
  7. const int INF = LLONG_MAX/2;
  8.  
  9. int primes[1000000];
  10.  
  11. void seive(){
  12. fill(primes, primes + 1000000, 1);
  13. primes[0] = primes[1] = 0;
  14. for(int i = 2 ; i*i < 1000000 ; i++){
  15. if(primes[i]){
  16. for(int j = i*i ; j < 1000000 ; j += i){
  17. primes[j] = 0;
  18. }
  19. }
  20. }
  21. for(int i = 1 ; i < 1000000 ; i++){
  22. primes[i] += primes[i-1];
  23. }
  24. }
  25. int factorial(int n){
  26. if(n==0){
  27. return 1;
  28. }
  29. return (n*(factorial(n-1)))%MOD;
  30. }
  31. bool isPrime(int n){
  32. if(n <= 1) return false;
  33. for(int i = 2 ; i*i <= n ; i++){
  34. if(n % i == 0) return false;
  35. }
  36. return true;
  37. }
  38.  
  39. int power(int a, int b){
  40. if(b == 0) return 1;
  41. a %= MOD;
  42. int value = power(a, b / 2);
  43. if(b % 2 == 0){
  44. return (value * value) % MOD;
  45. } else {
  46. return ((value * value) % MOD * (a % MOD)) % MOD;
  47. }
  48. }
  49.  
  50. int gcd(int a, int b){
  51. if(a == 0) return b;
  52. return gcd(b % a, a);
  53. }
  54. void solve() {
  55. int n1;
  56. cin>>n1;
  57. int A[n1];
  58. for(int i = 0 ; i<n1 ; i++){
  59. cin>>A[i];
  60. }
  61. int B[n1],C[n1];
  62. B[0] = max(A[0],0LL);
  63. C[n1-1] = max(A[n1-1],0LL);
  64. for(int i = 1 ; i<n1 ; i++){
  65. B[i] = max({(B[i-1]+A[i]),A[i],0LL});
  66. }
  67. for(int i = n1-2 ; i>=0 ; i--){
  68. C[i] = max({(C[i+1]+A[i]),A[i],0LL});
  69. }
  70. int D[n1],E[n1];
  71. D[0] = B[0];
  72. E[n1-1] = C[n1-1];
  73. int maxi = 0;
  74. for(int i = 1 ; i<n1 ; i++){
  75. D[i] = max(D[i-1],B[i]);
  76. }
  77. for(int i = n1-2 ; i>=0 ; i--){
  78. E[i] = max(E[i+1],C[i]);
  79. }
  80. for(int i = 0 ; i<n1-1 ; i++){
  81. int d = D[i]+E[i+1];
  82. maxi = max(maxi,d);
  83. }
  84. cout<<maxi<<endl;
  85. }
  86.  
  87. signed main(){
  88. ios::sync_with_stdio(false); cin.tie(NULL);
  89. //int t;
  90. //cin >> t;
  91. //while(t--){
  92. solve();
  93. //}
  94. return 0;
  95. }
Success #stdin #stdout 0.01s 5284KB
stdin
7
1
5
-3
4
-9
9
2
stdout
18