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  1. def task3(text):
  2.     text = text.lower()
  3.     longest = 0
  4.     cur = 0
  5.     for ch in text:
  6.         if ch == 'k':
  7.             cur += 1
  8.             longest = max(longest, cur)
  9.         else:
  10.             cur = 0
  11.     return longest
  12.  
  13.  
Success #stdin #stdout 0.13s 14052KB
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https://ideone.com/V8tezA
language:
Python 3 (python  3.12)
created:
2 days ago
visibility:
public

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