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  1. student_score = [78, 65, 92, 78, 90, 45, 83, 57, 96, 56]
  2. sum_score = 0
  3. for score in student_score:
  4. 	sum_score += score
  5. avreage_score = sum_score / len(student_score)
  6. print(f'总成绩为：{sum_score}, 平均成绩为：{avreage_score}')
  7. avreage_count = 0
  8. for score in student_score:
  9. 	if score >= avreage_score:
  10. 		avreage_count += 1
  11. 		print(f'大于等于平均成绩的个数为：{avreage_count}')
Success #stdin #stdout 0.07s 13860KB
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总成绩为：740, 平均成绩为：74.0
大于等于平均成绩的个数为：1
大于等于平均成绩的个数为：2
大于等于平均成绩的个数为：3
大于等于平均成绩的个数为：4
大于等于平均成绩的个数为：5
大于等于平均成绩的个数为：6
https://ideone.com/tcJ77R
language:
Python 3 (python  3.12)
created:
11 hours ago
visibility:
public

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